A student got twice as many sums wrong as he got right. If he attempted 48 sums

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Question

A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?

Options:

A . 12

B . 16

C . 18

D . 24

Answer: Option B
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 48 ⇔ 3x = 48 ⇔ x = 16.

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