Question
A man covers a total distance of 100 km on bicycle. For the first 2 hours, the speed was 20 km/ hr and for the rest of the journey, it came down to 10 km/hr. The average speed will be
Answer: Option C
Answer: (c)Distance covered in first 2 hours= 2 × 20 = 40 km.Remaining distance= 100 - 40 = 60 km.Time taken in covering 60 km at 10 kmph= $60/10$ = 6 hours∴ Required average speed= $\text"Total distance"/ \text"Total Time"$= $(100/{2+6})$ kmph = $(100/8)$ kmph= $25/2$ kmph = 12$1/2$ kmph
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Answer: (c)Distance covered in first 2 hours= 2 × 20 = 40 km.Remaining distance= 100 - 40 = 60 km.Time taken in covering 60 km at 10 kmph= $60/10$ = 6 hours∴ Required average speed= $\text"Total distance"/ \text"Total Time"$= $(100/{2+6})$ kmph = $(100/8)$ kmph= $25/2$ kmph = 12$1/2$ kmph
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