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A man covered a certain distance at some speed . Had he moved 3 kmph faster , he would have taken 40 minutes less . If he had moved 2 kmph  slower , he would have taken 40 minutes more . The distance (in km) is


Options:
A .  35
B .  `36 2/3`
C .  `37 1/2`
D .  40
Answer: Option D

Let distance = `x` km and usual rate = y kmph.

`x/y - (x)/(y + 3) = 40/60    or 2y(y + 3) = 9x` .............................................(I)

and ,` (x)/(y - 2) - x/y = 40/60   or  y(y - 2) =  3x` .........................................(II)

On dividing (I) by  (II), we get `x` = 40 km.




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