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A is twice as fast as B, and B is thrice as fast as C is. The journey covered by C in 1$1/2$ hours will be covered by A in
Options:
A .  30 minutes
B .  10 minutes
C .  1 hour
D .  15 minutes
Answer: Option D
Answer: (d)Time taken by C = t hoursTime taken by B = $t/3$ hoursand time taken by A = $t/6$ hoursHere, t = $3/2$ hours∴ Required time taken by A= $3/{2/6}$ hour = $1/4$ hour= $(1/4 × 60)$ minutes = 15 minutes

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