Question
A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Answer: Option B
THE NUMBER OF WAYS TO SELECT TWO MEN AND THREE WOMEN = ⁵C₂ * ⁶C₃
= (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)
= 200
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THE NUMBER OF WAYS TO SELECT TWO MEN AND THREE WOMEN = ⁵C₂ * ⁶C₃
= (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)
= 200
Was this answer helpful ?
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