Question
A car travelling with $5/7$ of its usual speed covers 42 km in 1 hour 40 min 48 sec. What is the usual speed of the car?
Answer: Option C
Answer: (c)1 hr 40 min 48 sec= 1 hr $(40 + 48/60)$ min= 1 hr $(40 + 4/5)$ min= 1 hr $204/5$ min= $(1 + 204/300)$ hr = $504/300$ hrSpeed = $42/{504/300}$ = 25 kmphNow, $5/7$ usual speed = 25Usual speed = ${25 × 7}/5$ = 35 kmph
Was this answer helpful ?
Answer: (c)1 hr 40 min 48 sec= 1 hr $(40 + 48/60)$ min= 1 hr $(40 + 4/5)$ min= 1 hr $204/5$ min= $(1 + 204/300)$ hr = $504/300$ hrSpeed = $42/{504/300}$ = 25 kmphNow, $5/7$ usual speed = 25Usual speed = ${25 × 7}/5$ = 35 kmph
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution