Question
A boy rides his bicycle 10km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. His average speed for the entire trip is approximately :
Answer: Option D
Answer: (d)Total distance = 10 + 12 = 22 kmTotal time = $10/12 + 12/10 = 244/120$ hoursRequired average speed= $\text"Total distance"/ \text"Total time"$= $22/{244/120} = 22/244 × 120$ = 10.8 km/hr. Using Rule 3,If a man travels different distances $d_1,d_2,d_3$, and so on with different speeds $s_1,s_2,s_3$, respectively then,Average speed = $({d_1 + d_2 + d_3 + ...})/{d_1/S_1 + d_2/S_2 + d_3/S_3 + ...}$
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Answer: (d)Total distance = 10 + 12 = 22 kmTotal time = $10/12 + 12/10 = 244/120$ hoursRequired average speed= $\text"Total distance"/ \text"Total time"$= $22/{244/120} = 22/244 × 120$ = 10.8 km/hr. Using Rule 3,If a man travels different distances $d_1,d_2,d_3$, and so on with different speeds $s_1,s_2,s_3$, respectively then,Average speed = $({d_1 + d_2 + d_3 + ...})/{d_1/S_1 + d_2/S_2 + d_3/S_3 + ...}$
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