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Question

A and B are two stations 390 km a part . A train starts from ! at 10 a.m. and travels towards  B at 65 kmph. Another train starts from  B at 11 a.m.  and travels towards A at 35 mph. At what time do they meet ?


Options:
A .  2.15 p.m.
B .  2.25 p.m.
C .  2.30 p.m.
D .  2.45 p.m.
Answer: Option A

Suppose they meet `x` hours after 10 a.m.  Then .

(Distance moved by first in `x` hrs) + ( Distance moved by second in `(x - 1)` hrs = 390

`:.`      `65x + 35(x - 1) = 390     rArr  100x = 425      rArr    x = 4 1/4`.

So, they meet 4 hrs. 15 min.

after 10 a.m.   i.e.,     at 2.15 p.m.




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