Question
(22!×P) is a perfect square. Find the least value of P, given that P belongs to a set of natural numbers.
Answer: Option A
:
A
22! can be written as 219×39×54×73×112×13×17×19.
To make it a perfect square, we need to multiply it by 2×3×7×13×17×19.
So, P = 176358.
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:
A
22! can be written as 219×39×54×73×112×13×17×19.
To make it a perfect square, we need to multiply it by 2×3×7×13×17×19.
So, P = 176358.
Was this answer helpful ?
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