Question
$$99 \times 21 - \root 3 \of ? = 1968$$
Answer: Option A
$$\eqalign{
& {\text{Let,}} \cr
& {\text{ }}99 \times 21 - \root 3 \of x = 1968 \cr
& {\text{Then,}} \cr
& \Leftrightarrow 2079 - \root 3 \of x = 1968 \cr
& \Leftrightarrow \root 3 \of x = 2079 - 1968 \cr
& \Leftrightarrow \root 3 \of x = 111 \cr
& \Leftrightarrow x = {\left( {111} \right)^3} \cr
& \Leftrightarrow x = 1367631 \cr} $$
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$$\eqalign{
& {\text{Let,}} \cr
& {\text{ }}99 \times 21 - \root 3 \of x = 1968 \cr
& {\text{Then,}} \cr
& \Leftrightarrow 2079 - \root 3 \of x = 1968 \cr
& \Leftrightarrow \root 3 \of x = 2079 - 1968 \cr
& \Leftrightarrow \root 3 \of x = 111 \cr
& \Leftrightarrow x = {\left( {111} \right)^3} \cr
& \Leftrightarrow x = 1367631 \cr} $$
Was this answer helpful ?
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