Answer: Option D
$$\eqalign{
& = 262144 \cr
& = 8 \times 8 \times 8 \times 8 \times 8 \times 8 \cr
& = {8^6} \cr
& \therefore \root 3 \of {262144} \cr
& = {8^2} \cr
& = 64 \cr
& {\text{Let, }} \cr
& {\text{1728}} \div \root 3 \of {262144} \times x - 288 = 4491 \cr
& {\text{Then,}} \cr
& \Leftrightarrow 1728 \div 64 \times x - 288 = 4491 \cr
& \Leftrightarrow 27x = 4779 \cr
& \Leftrightarrow x = \frac{{4779}}{{27}} \cr
& \Leftrightarrow x = 177 \cr} $$
$$\eqalign{
& 8|262144 \cr
& - - - - - - - - \cr
& 8|\,\,\,32768 \cr
& - - - - - - - - \cr
& 8|\,\,\,\,4096 \cr
& - - - - - - - - \cr
& 8|\,\,\,\,\,512 \cr
& - - - - - - - - \cr
& 8|\,\,\,\,\,\,64 \cr
& - - - - - - - - \cr
& 8|\,\,\,\,\,\,\,8 \cr
& - - - - - - - - \cr} $$