if the bridge is at the height of 4 from the banks. Find the width of the river (take √3 = 1.732 )

∠CAD =

∠CBD =

so we have to calculate width of the river AB =?

So in △ACD according to basic concept-

CD = 1 part = 4m =

AC = 4

So in △BCD according to basic concept-

CD = 1 part = 4m;

AC = √3 part = 4m * √3

AC = 4 √3 m =

AC = 6.92

So width of the river BC = AC + BC

BC = 4 + 6.92

BC = 10.92

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