# Compound Intrest

**Vedic Maths trick to find Compound Intrest**

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A sum of money at compounded interest double it self in **2** years .In how many years will it amount to **8** times it self.

Let a sum( P ) for 2 years = Amount ( 2P )

Putting the value in Compound intrest formula:

Compound Interest = C.I.

Principal = P

Rate Of Interes = r

Time = n

**P [ 1 + **^{r} / _{100} ]^{2} = 2P

** [ 1 + **^{r} / _{100} ]^{2} = 2

8 times can be written as:

8 times = 8P = (2)^{3}P

**[ [ 1 + **^{r} / _{100} ]^{2} ]^{3} = (2)^{3}

** [ 1 + **^{r} / _{100} ]^{6} = (2)^{3}

**The sum will be 8 times in 6 years **

^{r}/

_{100}]

^{2}= 2P

^{r}/

_{100}]

^{2}= 2

^{r}/

_{100}]

^{2}]

^{3}= (2)

^{3}

^{r}/

_{100}]

^{6}= (2)

^{3}