On 15 April 1998 was Wednesday. so What was The day on 7 May 1996.

First of all we must Know:

0^th odd day=Sunday

1^th odd day=Monday

2^th odd day=Tuesday

3^th odd day=Wednesday

4^th odd day=Thursday

5^th odd day=Friday

6^th odd day=Saturday

STEP 1 :

First of all we calculate the total number of days between the date 7 May 1996 to 15 April 1998

Number of Days in1996
May	24
Jun	30
Jul	31
Aug	31
Sep	30
Oct	31
Nov	30
Dec	31
Number of Days in1997
Jan	31
Feb	28
Mar	31
Apr	30
May	31
Jun	30
Jul	31
Aug	31
Sep	30
Oct	31
Nov	30
Dec	31
Number of Days in1998
Jan	31
Feb	28
Mar	31
Apr	15
Total No. of Days	708

STEP 2 :

Now we calculate the odd day number and for that we have to divide the total number of days with 7(1week=7days) and reminder will be our odd day number.

708 / 7 = 1 odd days (1 is Reminder)

STEP 3 :

As we know given day is Wednesday which is 3^th odd day

Let the odd Number associated with the day on 7 May 1996 is 'X'
Wednesday on 15 April 1998 = 3 odd day
so 'X + 1 = 3'
Now we have to put the value of 'X' as after dividing 'X + 1' with '7' reminder will be '3'
so 'X = 2' and day is 'Tuesday'

Watch Youtube video of Calendar for better understanding.