Fractions And Decimals(7th Grade > Mathematics ) Questions and answers for exam Preparation

7th Grade > Mathematics

FRACTIONS AND DECIMALS MCQs

Fractions, Decimals

Total Questions : 227 | Page 2 of 23 pages

Question 11. Compare the following and fill in with an appropriate symbol

>
=
Not comparable

Discuss Question

Answer: Option C. -> =
:
C
In the first figure, 27 parts are shaded out of 100 , so the decimal is 0.27
In the second figure, 27 parts are shaded out of 100, so the decimal is 0.27
Hence both thedecimals are equal

Question 12. Find :

3 \div \frac{6}{7} + 7 \div \frac{21}{2}

- 2 \div 5

31330
32330
32130
31130

Discuss Question

Answer: Option B. -> 32330
:
B

3 \div \frac{6}{7} + 7 \div \frac{21}{2} - 2 \div 5 ∴ 3 \times \frac{7}{6} + 7 \times \frac{2}{21} - \frac{2}{5} ∴ \frac{7}{2} + \frac{2}{3} - \frac{2}{5} L C M o f 2, 3, 5 i s 30 ∴ \frac{7}{2} = \frac{7 \times 15}{2 \times 15} = \frac{105}{30} \frac{2}{3} = \frac{2 \times 10}{3 \times 10} = \frac{20}{30} \frac{2}{5} = \frac{2 \times 6}{5 \times 6} = \frac{12}{30} ∴ \frac{105 + 20 - 12}{30} = \frac{113}{30} ∴ \frac{113}{30} = 3 \frac{23}{30}

Question 13. Simplify the following expression and choose the correct answer:

\frac{0 \times (\frac{5}{9} \times \frac{2}{3}) + \frac{5}{6} \times 9 \times 0}{(\frac{4}{5} + \frac{3}{5} + \frac{1}{2})}

Discuss Question

Answer: Option D. -> 0
:
D
Concentrate on numerator. The expression has '

0

' multiplied to it, and any numbermultiplied by'

0

' is '

0

'.
And 0 divided by any numberalways '

0

'.
Hence the answer is '

0

Question 14. A person bought

3 \frac{1}{2} k g

of apples,

2 \frac{2}{3} k g

of grapes and

1 \frac{1}{3} k g

of oranges. He wants to divide them among

4

people. Find the amount of fruits(in kg) that each person will receive.

138 kg
158 kg
178 kg
278 kg

Discuss Question

Answer: Option C. -> 178 kg
:
C
First, let usdo the conversion of mixed fractions into improper fractions.
i.e

3 \frac{1}{2} = \frac{(2 \times 3) + 1}{2} = \frac{7}{2}

2 \frac{2}{3} = \frac{(3 \times 2) + 2}{3} = \frac{8}{3}

, and

1 \frac{1}{3} = \frac{(3 \times 1) + 1}{3} = \frac{4}{3}

Total quantityof fruits = (\frac{7}{2} + \frac{8}{3} + \frac{4}{3}) k g

= \frac{7}{2} + 4

= \frac{7}{2} + \frac{8}{2}

= \frac{15}{2}

kg
When

\frac{15}{2} k g

is divided among 4people,
each person's share

= \frac{\frac{15}{2}}{4} k g

= (\frac{15}{2} \times \frac{1}{4}) k g

= \frac{15}{8} k g

= 1 \frac{7}{8} k g

Hence, each person gets

(1 \frac{7}{8}) k g

of fruits.

Question 15. Solve

\frac{1}{3} - (\frac{5}{6} \times \frac{9}{18}) + \frac{2}{9}

Discuss Question

Answer: Option B. -> 536
:
B

\frac{1}{3} - (\frac{5}{6} \times \frac{9}{18}) + \frac{2}{9}

= \frac{1}{3} - (\frac{15}{36}) + \frac{2}{9}

= \frac{1}{3} - \frac{15}{36} + \frac{2}{9}

Taking L.C.M of denominators,

\frac{12 - 15 + 8}{36} = \frac{5}{36}

Question 16.

(60 \times 0.06 \times 6) - (0.0006 \times 600 \times 0.6)

is equal to:

21.384
213.84
2.1834
20.484

Discuss Question

Answer: Option A. -> 21.384
:
A

(60 \times 0.06 \times 6) - (0.0006 \times 600 \times 0.6)

= (21.6) - (0.216)

= 21.384

Question 17.

(12.4 + 9.6) \times (0.1 + 0.001)

_____

(1.24 \times 10.96) \times 0.2

>
=
can't say

Discuss Question

Answer: Option B. -> 21.384
:
B

(12.4 + 9.6) \times (0.1 + 0.001)

= 22.0 \times 0.101

= 2.222

And,

(1.24 \times 10.96) \times 0.2

= 13.59 \times 0.2

= 2.718

2.718

is greater than

2.222

Therefore,

(12.4 + 9.6) \times (0.1 + 0.001)

(1.24 \times 10.96) \times 0.2

Question 18. On multiplying a decimal number by

100

, we shift the decimal point (i) ______ places to the (ii) ______ and on dividing a decimal number by

100

, we shift the decimal point, (iii)_______ places to the (iv) _______.

i) two ii) left iii) two iv) right
i) one ii) right iii) one iv) left
i) two ii) right iii) one iv) left
i) two ii) right iii) two iv) left

Discuss Question

Answer: Option D. -> i) two ii) right iii) two iv) left
:
D
Let's take an example and visualize.

2.48 \times 100 = 248.0

[Decimal point shifted two places to the right]

2480 \div 100 = \frac{2480}{100} = 24.80

[Decimal point shifted two places to the left]

Question 19. Cindy had 97 candies. She gave Joey

\frac{23}{97}

of the candies. How many candies will Joey have?

Discuss Question

Answer: Option C. -> 23
:
C
It is given that Cindy had 97 candies.
She gave Joey

\frac{23}{97}

of candies.
The total number of candies is 97 which is the whole out of which 23 candies were given to Joey.
Hence, Joey has 23 candies.

Question 20. Simon had 28 flowers in his garden. 13 flowers wilted. What fraction of flowers are still blooming in his garden now?

1328
1528
1315
515

Discuss Question

Answer: Option B. -> 1528
:
B
Number of flowers in Simon's garden = 28
Number of flowers that wilted = 13
Number of flower that are still blooming =Total number of flowers - Number of flowers that wilted
Number of flowers still blooming = 28 - 13 = 15
The fraction of flowers that are still blooming =