$\frac{\left(\frac{1}{2}\right)\times \left(\frac{1}{2}\right)+\left(\frac{1}{2}\right)}{\left(\frac{1}{2}\right)+\left(\frac{1}{2}\right)\times \left(\frac{3}{4}\right)}$ = $\frac{\left(\frac{1}{4}\right)+\left(\frac{1}{2}\right)}{1\times \left(\frac{3}{4}\right)}$ = $\frac{\left(\frac{3}{4}\right)}{\left(\frac{3}{4}\right)}=1$

Given $[5\frac{1}{4}-\frac{2}{5}\times 5\frac{5}{9}+(\frac{1}{2}+\frac{3}{4})]$
Apply BODMAS rule to solve

= $[\frac{21}{4}-(\frac{2}{5}\times \frac{50}{9})+\frac{5}{4}]$

= $[\frac{21}{4}-(\frac{20}{9})+\frac{5}{4}]$

Taking LCM of denominators, we have

$\frac{189-80+45}{36}=\frac{154}{36}=\frac{77}{18}$
$[5\frac{1}{4}-\frac{2}{5}\times 5\frac{5}{9}+(\frac{1}{2}+\frac{3}{4})]=\frac{77}{18}$

First, let us do the conversion of mixed fractions into improper fractions.
i.e  $3\frac{1}{2}=\frac{(2\times 3)+1}{2}=\frac{7}{2}$
     
$2\frac{2}{3}=\frac{(3\times 2)+2}{3}=\frac{8}{3}$, and 
     
$1\frac{1}{3}=\frac{(3\times 1)+1}{3}=\frac{4}{3}$
$\text{Total quantity of fruits}=(\frac{7}{2}+\frac{8}{3}+\frac{4}{3})kg$
                                     
                                      $=\frac{7}{2}+4$
                                      $=\frac{7}{2}+\frac{8}{2}$ kg
   
                                      $=\frac{15}{2}$ kg

When $\frac{15}{2}kg$ is divided among 4 people,

each person's share $=\frac{\frac{15}{2}}{4}kg$
                                 
                                  $=(\frac{15}{2}\times \frac{1}{4})kg$
                                  $=\frac{15}{8}kg$
                                  $=1\frac{7}{8}kg$
Hence, each person gets $\left(1\frac{7}{8}\right)kg$ of fruits. 

$\frac{\frac{5}{2}+\frac{7}{3}+\frac{9}{4}}{\frac{1}{10}\times \frac{2}{5}\times \frac{125}{6}}$
$=\frac{\frac{85}{12}}{\frac{5}{6}}$

$=\frac{85}{12}\times \frac{6}{5}$
$=\frac{17}{2}=8.5$

Let the total distance to be covered $=dkm$
Then, $\frac{1}{8}\times d$ = $56km$

$\text{d = (56}\times \text{8)km = 448km}$

$\text{Remaining distance = (448 - 56)km = 392km}$

Concentrate on numerator. The expression has '$0$' multiplied to it, and any number multiplied by '$0$' is '$0$'.
And 0 divided by any number always '$0$'.
Hence the answer is '$0$'.

Consider the following example.              
Suppose you have a pizza.
Divide the whole pizza into $4$ parts.
Now, take $3$ parts out of the $4$ parts.
These $3$ parts represent the fraction $3$ out of $4$, i.e., $\frac{3}{4}$.
i.e., a fraction is the ratio of the number of divisions considered to the total number of divisions.

$a\frac{b}{c}$ is called a mixed fraction.
Here, 'a' is whole number part and $\frac{b}{c}$ is the fractional part.
e.g. $2\frac{3}{4}$, $5\frac{1}{6}$

$a\frac{b}{c}=a+\frac{b}{c}$
e.g:  $2\frac{3}{4}=$ $2+\frac{3}{4}$
 

In an improper fraction, the numerator is greater than the denominator and denominator should not be equal to zero.

e.g. $\frac{61}{5}$,  $\frac{7}{6}$, $\frac{9}{4}$,$\frac{66}{21}$ etc