Answer: Option B. -> 0.4
:
B
Consider 0.9, it is greater than 0.7 as well as 0.3, hence it cannot lie between 0.3 and 0.7. Similarly,0.2 and 0.8 cannot lie between 0.3 and 0.7.
But, 0.4is greater than 0.3 and less than 0.7. Hence, it lies between 0.3 and 0.7.
OR
0.2 has 2 tenths, 0.3 has 3 tenths, 0.4 has 4 tenths, 0.7 has 7 tenths, 0.8 has 8 tenths and 0.9 has 9 tenths.
2 tenths$<$3 tenths$<$4 tenths$<$7 tenths$<$8 tenths$<$9tenths
$⟹0.2<0.3<0.4<0.7<0.8<0.9$
Thus, 0.4 lies between 0.3 and 0.9.

Answer: Option A. -> 83
:
A
Among the options, only $\frac{8}{3}$ is the fractionwhich will give non-terminatingdecimal. This is because all other options have denominator having on 2 and 5 as prime factors after standardising.

Answer: Option B. -> ₹1.75
:
B
Amount each child will get $=\frac{\text{Total money}}{\text{Number of children}}=\frac{70}{40}=\frac{7}{4}=\frac{7\times 25}{4\times 25}=\frac{175}{100}=₹1.75$
So, each child will get ₹1.75.

Answer: Option D. -> 486.132 
:
D
Addition should be done as follows:
59.365
+ 362.580
+ 64.187
486.132
So, the answer is 486.132.

Answer: Option B. -> 2 and 3   
:
B
For like fractions, the denominators should be the same.

Answer: Option D. -> Infinite  
:
D
There are infinite fractions on a number line. The two fractions given in the question are two points on the number line. Between these two points, there exists infinite points.So, infinite fractions exist between two points on a number line.

Answer: Option A. -> 156
:
A
Let us first convert the mixed fractions $15\frac{5}{3}$and $17\frac{3}{2}$ to improper fractions.
i.e., $15\frac{5}{3}=\frac{15\times 3+5}{3}=\frac{50}{3}$and $17\frac{3}{2}=\frac{17\times 2+3}{3}=\frac{37}{2}$
Now, $17\frac{3}{2}-15\frac{5}{3}=\frac{37}{2}-\frac{50}{3}=\frac{111-100}{6}=\frac{11}{6}=1\frac{5}{6}$

Answer: Option A. -> True
:
A
Let us take the full length of the train as L.
24 compartments---------------L
1 compartment--------------=$\frac{1}{24}\times L$

Answer: Option C. -> 34
:
C
Old animals = 40 - 10 = 30
Fraction of old animals presently in the zoo =$\frac{30}{40}=\frac{3}{4}$

Answer: Option A. -> Kushagra
:
A
Total distance to be covered = 5 km
Distance covered by Manish = 2 km
$\Rightarrow$ Fraction of the distance covered by Manish =$\frac{2}{5}$
Fraction of the distance covered by Kushagra =$\frac{1}{2}$
To compare these fractions, we write them as like fractions.
$\frac{2}{5}=\frac{2\times 2}{5\times 2}=\frac{4}{10}$
$\frac{1}{2}=\frac{1\times 5}{2\times 5}=\frac{5}{10}$
Since $\frac{4}{10}<\frac{5}{10}$,
$\frac{2}{5}<\frac{1}{2}$
Therefore, Kushagra ran more.