Question
Wthat is the unit digit in (`7^95` -` 3^58` ) ?
Answer: Option B
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Unit digit in `7^95` = Unit digit in [`(7^4)^23` x `7^3` ] = ( 1 x 3 ) = 3.
Uni digit in `3^58` = Unit digit in [`(3^4)^14` x `3^2` ] = ( 1 x 9 ) = 9.
Unit digit in `(7^95 - 3^58 )` = ( 13 - 9 ) = 4.
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