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Question

Which one of the following numbers will completely divide (`3^25` + `3^26` + `3^27` + `3^28`) ?


Options:
A .  11
B .  16
C .  25
D .  30
Answer: Option D

(`3^25` + `3^26` + `3^27` + `3^28`)  = `3^25` `xx` (1+ 3 + `3^2` + `3^3`) = `3^25` `xx` 40

                               = `3^24` `xx` 3`xx` 4 `xx` 10 = (`3^24` `xx` 4`xx` 30), which is divisible by 30.




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