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Question

Which of the given numbers is divisible by 3, 7, 9 and 11?


Options:
A .  None of these
B .  1890
C .  4230
D .  6237
Answer: Option D

1. Testing 4230
4 + 2 + 3 + 0 = 9. 9 is divisible by 3. Hence 4230 is also divisible by 3
4 + 2 + 3 + 0 = 9. 9 is divisible by 9. Hence 4230 is also divisible by 9
423 - (2 × 0) = 423
42 - (2 × 3) = 36
36 is not divisible by 7. Hence 4230 is not divisible by 7
Hence 4230 does not meet all divisibility conditions
2. Testing 1890
1 + 8 + 9 + 0 = 18. 18 is divisible by 3. Hence 1890 is also divisible by 3
1 + 8 + 9 + 0 = 18. 18 is divisible by 9. Hence 1890 is also divisible by 9
189 - (2 × 0) = 189
18 - (2 × 9) = 0
Hence 1890 is divisible by 7
1 + 9 = 10
8 + 0 = 8
10 - 8 = 2
2 is not divisible by 11. Hence 1890 is not divisible by 11
Hence 1890 does not meet all divisibility conditions
2. Testing 6237
6 + 2 + 3 + 7 = 18. 18 is divisible by 3. Hence 6237 is also divisible by 3
6 + 2 + 3 + 7 = 18. 18 is divisible by 9. Hence 6237 is also divisible by 9
623 - (2 × 7) = 609
60 - (2 × 9) = 42
42 is divisible by 7. Hence 6237 is also divisible by 7.
6 + 3 = 9
2 + 7 = 9
9 - 9 = 0
Hence 6237 is divisible by 11
We got that 6237 is divisible by 3, 9, 7 and 11. Hence this is the answer.




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