Question
When the ground is horizontal, \(α=\frac{π}{2}\) in constant K. What will be the radial stress σᵣ due to inclined line load at the horizontal ground surface?
Answer: Option B
Answer: (b).\(σ_r=\frac{2Q cos(θ-β)}{πr}\)
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Answer: (b).\(σ_r=\frac{2Q cos(θ-β)}{πr}\)
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