Question
What will be the remainder when (`67^67` + 67 ) is divided by 68 ?
Answer: Option C
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(`x^n` + 1) will be divisible by ( `x` + 1) only when n is odd
`therefore` (`67^67` + 1) will be divisible by ( 67 + 1)
`therefore` (`67^67` + 1) + 66. when divided by 68 will give 66 as remainder.
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