Question
What is the unit digit in `{(264)^102 + (264)^103}` ?
Answer: Option A
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`(264)^102 + (264)^103`
= `(264)^102 ( 1 + 264)`
= `(264)^102 xx 265`
=Required unit digit = unit digit in `[ (4)^102 xx 5]`
= unit digit in `[(4^4)^25 xx 4^2 xx 5]`
= unit digit in ( 6 x 6 x 5) = 0.
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