Question
What is the greater of the two numbers whose product is 2560, given that the sum of the two numbers exceeds their difference by 64?
Answer: Option E
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Let the greater and the smaller number be g and s respectively.gs = 2560g + s exceeds g - s by 64 i.e., g + s - (g - s) = 64i.e., 2s = 64 => s = 32.g = 2560/s = 80.
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