Question
Vishwas borrowed a total amount of Rs. 30000, part of it on simple interest rate of 12 p.c.p.a. and remaining on simple interest rate of 10 p.c.p.a. If at the end of 2 year she paid in all Rs. 36480 to settle the loan amount, what was the amount borrowed at 12 p.c.p.a ?
Answer: Option A
Let the sum borrowed at 12% p.a. be Rs. x
and that borrowed at 10% p.a. be Rs. (30000 - x)
S.I. at the end of 2 years
= Rs. (36480 - 30000)
= Rs. 6480
$$\therefore \left( {\frac{{x \times 12 \times 2}}{{100}}} \right) + $$ $$\left[ {\frac{{\left( {30000 - x} \right) \times 10 \times 2}}{{100}}} \right]$$ $$ = 6480$$
$$\eqalign{
& \Leftrightarrow 24x + 600000 - 20x = 648000 \cr
& \Leftrightarrow 4x = 48000 \cr
& \Leftrightarrow x = 12000 \cr} $$
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Let the sum borrowed at 12% p.a. be Rs. x
and that borrowed at 10% p.a. be Rs. (30000 - x)
S.I. at the end of 2 years
= Rs. (36480 - 30000)
= Rs. 6480
$$\therefore \left( {\frac{{x \times 12 \times 2}}{{100}}} \right) + $$ $$\left[ {\frac{{\left( {30000 - x} \right) \times 10 \times 2}}{{100}}} \right]$$ $$ = 6480$$
$$\eqalign{
& \Leftrightarrow 24x + 600000 - 20x = 648000 \cr
& \Leftrightarrow 4x = 48000 \cr
& \Leftrightarrow x = 12000 \cr} $$
Was this answer helpful ?
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