Question
Unit digit in $(264)^102 + (264)^103$ is :
Answer: Option B
Answer: (b)Unit digit in $(264)^4$ i.e. 4 × 4 × 4 × 4 is 6Unit digit in $(264)^100$ is also 6. Now, $(264)^102 = (264)^100 × (264)^2$ = (Unit digit 6) × (Unit digit 6)=36∴ Unit digit is 6 Similarly,$(264)^103 + (264)^100 × (264)^3$ = (Unit digit 6) × (Unit digit 4)=24∴ Unit digit is 4Therefore, the unit digit in $(264)^102 + (264)^103$ is6 + 4 = 10 i.e. 0.
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Answer: (b)Unit digit in $(264)^4$ i.e. 4 × 4 × 4 × 4 is 6Unit digit in $(264)^100$ is also 6. Now, $(264)^102 = (264)^100 × (264)^2$ = (Unit digit 6) × (Unit digit 6)=36∴ Unit digit is 6 Similarly,$(264)^103 + (264)^100 × (264)^3$ = (Unit digit 6) × (Unit digit 4)=24∴ Unit digit is 4Therefore, the unit digit in $(264)^102 + (264)^103$ is6 + 4 = 10 i.e. 0.
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