Question
Two numbers are such that the square of one is 224 less than 8 times the square of the other. If the numbers be in
the ratio of 3: 4, the numbers are :
Answer: Option A
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Let the numbers be `3x and 4x .` Then
`(4x)^2` = 8 x `(3x)^2` - 224 `hArr` `16x^2` = `72x^2` - 224 `hArr` `56x^2` = 224 `hArr` `x^2` = 4 `hArr` `x` =2
So the numbers are 6 and 8.
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