Question
Two equal sums of money were lent at simple interest at 11% p.a. for `3 1/2` years and `4 1/2` years respectively . If the difference in interest for two periods was Rs. 412.50 then each sum is :
Answer: Option C
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Let each sum be Rs. `x` , Then ,
`((x xx 11 xx 9)/(100 xx 2)) - ((x xx 11 xx 7)/(100 xx 2))` = 41250
`hArr (99x - 77x) = 82500`
`hArr 22x = 82500`
`hArr x = 3750`
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