Question
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option D
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Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 \(\Leftrightarrow\) x = 11.
Therefore Third integer = x + 4 = 15.
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