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Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:


Options:
A .  9
B .  11
C .  13
D .  15
Answer: Option D

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3   Three Times The First Of Three Consecutive Odd Integers Is 3...   x = 11.

Three Times The First Of Three Consecutive Odd Integers Is 3... Third integer = x + 4 = 15.


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