Answer: Option A
Answer: (a)
Let A, B, C and D denote the amounts with these individuals respectively.
Then, A + B = C + D, B + D > A + C, A > B.
Now, B + D > A + C and A > B = B + D > A + C > B + C (∫ A > B) = B + D > B + C = D > C.
Also, A + B = c + D, A > B and D > C = 2B < A + B = C + D < 2C = 2B < 2C = C > B. Now, A > B, C > B, D > C = A > B, D > C > B.
Thus, each one of A, D and C has more amount than B.
Hence, B has the least amount.