Question
The value of the following is : $√{12+√{12+√{12 +...}}}$
Answer: Option C
Answer: (c)x = $√{12+√{12+√{12 +...}}}$On squaring both sides,$x^2 = 12 + √{12+√{12+√{12 +...}}}$$x^2$ = 12 + x$x^2$ - x - 12 = 0$x^2$ - 4x + 3x - 12 = 0x (x - 4) + 3 (x - 4) = 0(x - 4) (x + 3) = 0x = 4 because x ≠ - 3
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Answer: (c)x = $√{12+√{12+√{12 +...}}}$On squaring both sides,$x^2 = 12 + √{12+√{12+√{12 +...}}}$$x^2$ = 12 + x$x^2$ - x - 12 = 0$x^2$ - 4x + 3x - 12 = 0x (x - 4) + 3 (x - 4) = 0(x - 4) (x + 3) = 0x = 4 because x ≠ - 3
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