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Question

The sum of two positive integers multiplied by  the bigger number is 204, and their difference multiplied by the smaller number is 35. The numbers are:


Options:
A .  12, 5
B .  13, 4
C .  14, 3
D .  24,10
Answer: Option A

Let the numbers be  `x` and y such that `x` > y.  Then

`x(x + y)` =  204    `rArr`   `x^2  + xy` = 204...............(i) and y(`x` - y) = 35   `rArr` ` xy - y^2` =  35 ............(ii)

Subtracting (ii) from (i), we get : `x^2 + y^2` =  169

The only triplet satisfying this condition is (12, 5, 13) Thus , `x` = 12, y= 5.




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