Question
The sum of three numbers is 68. If the ratio between first and second be 2:3 and that between second and third be 5:3 then the second number is:
Answer: Option A
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Numbers be a, b, c
=> a/b = 2/3, b/c = 5/3
=> a/b = 10/15 and b/c = 15/9
=> a:b:c = 10:15:9
Numbers be 10x, 15x and 9x.
=> 10x + 15x + 9x = 68
=> 34 x = 68
=> x = 2
Second number = 15 x = 15 × 2 = 30
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