Question
The sum of three consecutive odd natural numbers each divisible by 3 is 72. What is the largest among them?
Answer: Option A
Answer: (a)Let the numbers be 3x, 3x + 3 and 3x + 63x + 3x + 3 + 3x + 6 = 72 9x + 9 = 729x = 72 – 9 = 63x =$63/9$ = 7∴ Largest number = 3x + 6 = 3 × 7 + 6 = 27
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Answer: (a)Let the numbers be 3x, 3x + 3 and 3x + 63x + 3x + 3 + 3x + 6 = 72 9x + 9 = 729x = 72 – 9 = 63x =$63/9$ = 7∴ Largest number = 3x + 6 = 3 × 7 + 6 = 27
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