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Question

The sum of  a  number  and its reciprocal is one eight of 34. What is the product of the number and its

square root ?


Options:
A .  8
B .  27
C .  32
D .  None of these
Answer: Option A

Let the number be `x` . Then,  `x + 1/x` =  `34/8`  `hArr`  `(x^2 + 1)/(x)` = `34/8`  `hArr`  `8x^2 - 34x + 8 ` = 0

`hArr` `4x^2 - 17x + 4` = 0  `hArr`  `(4x - 1) ( x - 4)` =  0    `hArr`   `x` = 4

[neglecting `x = 1/4`, as  `x` is a natural  no.]

`:.`   Required number =  `4 xx sqrt(4)` =  4 x 2 = 8.




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