Question
The sum of a number and its reciprocal is one eight of 34. What is the product of the number and its
square root ?
Answer: Option A
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Let the number be `x` . Then, `x + 1/x` = `34/8` `hArr` `(x^2 + 1)/(x)` = `34/8` `hArr` `8x^2 - 34x + 8 ` = 0
`hArr` `4x^2 - 17x + 4` = 0 `hArr` `(4x - 1) ( x - 4)` = 0 `hArr` `x` = 4
[neglecting `x = 1/4`, as `x` is a natural no.]
`:.` Required number = `4 xx sqrt(4)` = 4 x 2 = 8.
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