Question
The sum of money which when given on compound interest at 18% per annum would fetch Rs 960 more when the interest is payable half-yearly then when it was payable annually for 2 years is = ?
Answer: Option D
Rate of interest = 18%
Time = 2 year
When the interest is payable half yearly
Then, rate of interest = 9%
Time = 4 half - years
Let the principal be Rs. x
$$\eqalign{
& {\text{C}}{\text{.I}}{\text{. = }}x\left[ {{{\left( {1 + \frac{R}{{100}}} \right)}^T} - 1} \right]{\text{ }} \cr
& = x\left[ {{{\left( {1 + \frac{9}{{100}}} \right)}^4} - 1} \right] \cr
& = x\left[ {{{\left( {\frac{{109}}{{100}}} \right)}^4} - 1} \right] \cr
& = x\left[ {1.4116 - 1} \right] \cr
& = Rs.\,0.4116x \cr
& {\text{According to question}} \cr
& = x\left[ {{{\left( {1 + \frac{{18}}{{100}}} \right)}^2} - 1} \right] \cr
& = x\left[ {{{\left( {\frac{{118}}{{100}}} \right)}^2} - 1} \right] \cr
& = x\left[ {{{\left( {1.18} \right)}^2} - 1} \right] \cr
& = x\left[ {1.3924 - 1} \right] \cr
& = Rs.\,0.3924x \cr
& {\text{According to question,}} \cr
& 0.4116x - 0.3924x = 960 \cr
& \Rightarrow x = \frac{{960}}{{0.0192}} \cr
& \Rightarrow x = \frac{{960 \times 10000}}{{192}} \cr
& \Rightarrow x = 50000 \cr
& {\text{Hence, sum of money}} \cr
& {\text{ = Rs. 50000}} \cr} $$
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Rate of interest = 18%
Time = 2 year
When the interest is payable half yearly
Then, rate of interest = 9%
Time = 4 half - years
Let the principal be Rs. x
$$\eqalign{
& {\text{C}}{\text{.I}}{\text{. = }}x\left[ {{{\left( {1 + \frac{R}{{100}}} \right)}^T} - 1} \right]{\text{ }} \cr
& = x\left[ {{{\left( {1 + \frac{9}{{100}}} \right)}^4} - 1} \right] \cr
& = x\left[ {{{\left( {\frac{{109}}{{100}}} \right)}^4} - 1} \right] \cr
& = x\left[ {1.4116 - 1} \right] \cr
& = Rs.\,0.4116x \cr
& {\text{According to question}} \cr
& = x\left[ {{{\left( {1 + \frac{{18}}{{100}}} \right)}^2} - 1} \right] \cr
& = x\left[ {{{\left( {\frac{{118}}{{100}}} \right)}^2} - 1} \right] \cr
& = x\left[ {{{\left( {1.18} \right)}^2} - 1} \right] \cr
& = x\left[ {1.3924 - 1} \right] \cr
& = Rs.\,0.3924x \cr
& {\text{According to question,}} \cr
& 0.4116x - 0.3924x = 960 \cr
& \Rightarrow x = \frac{{960}}{{0.0192}} \cr
& \Rightarrow x = \frac{{960 \times 10000}}{{192}} \cr
& \Rightarrow x = 50000 \cr
& {\text{Hence, sum of money}} \cr
& {\text{ = Rs. 50000}} \cr} $$
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