Question
The sum of money that yields a compound interest of Rs.420 during the second year at 5% p.a is
Answer: Option C
Answer: (c)Using Rule 1,CI = P$[(1 + R/100)^T –1] - {PR}/100$420 = P$[(1 + 5/100)^2 - 1] - {P × 5}/100$420 = P$[(21/20)^2 - 1] - {5P}/100$420 = ${41P}/400 - {5P}/100 = {21P}/400$P = ${420 × 400}/21$ = Rs.8000
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Answer: (c)Using Rule 1,CI = P$[(1 + R/100)^T –1] - {PR}/100$420 = P$[(1 + 5/100)^2 - 1] - {P × 5}/100$420 = P$[(21/20)^2 - 1] - {5P}/100$420 = ${41P}/400 - {5P}/100 = {21P}/400$P = ${420 × 400}/21$ = Rs.8000
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