Question
The sum of first 50 odd natural numbers is
Answer: Option D
Answer: (d)S = 1 + 3 + 5 + ..... to 50 termsHere, a = 1; d = 3 – 1 = 2; n = 50S = $n/2[2a + (n - 1)d]$= $50/2[2×1+ (50 - 1) ×2]$= 25 (2 + 98) = 25 × 100 = 2500
Was this answer helpful ?
Answer: (d)S = 1 + 3 + 5 + ..... to 50 termsHere, a = 1; d = 3 – 1 = 2; n = 50S = $n/2[2a + (n - 1)d]$= $50/2[2×1+ (50 - 1) ×2]$= 25 (2 + 98) = 25 × 100 = 2500
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution