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Question


The sum of first 45 natural numbers is:

Options:
A .  1035
B .  1280
C .  2070
D .  2140
Answer: Option A

Let Sn = (1 + 2 + 3 + ... + 45)


This is an A.P. in which a = 1, d = 1, n = 45 and l = 45



The Sum Of First 45 Natural Numbers Is:Sn =
n
(a + l)
=
45
x (1 + 45)   = (45 x 23)   = 1035
2
2


Required sum = 1035.



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