Question
The sum of all two digit numbers divisible by 5 is
Answer: Option D
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Required numbers are 10,15,20,25, .............95,
This is an A.P. in which a = 10, d = 5 and `l` = 95
Let the number of terms in it be n. Then
`t_n` = 95 `rArr` a + (n - 1)d = 95
`rArr` 10 + (n - 1) x 5 =95 `rArr` ( n-1) x 5 = 85 `rArr` (n - 1) = 17 `rArr` n = 18.
Required sum = `n/2` (a + `l`) = `18/2` (10 + 95) = (9 x 105) = 945.
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