Question
The sum of all the natural numbers from 51 to 100 is
Answer: Option D
Answer: (d)We have, 1 + 2 + 3 ........ + n = ${n(n+1)}/2$51 + 52 + ..... + 100 = (1 + 2 + ....... 100) – (1 + 2 + ... + 50) = ${100×101}/2 - {50×51}/2$= 5050 – 1275 = 3775
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Answer: (d)We have, 1 + 2 + 3 ........ + n = ${n(n+1)}/2$51 + 52 + ..... + 100 = (1 + 2 + ....... 100) – (1 + 2 + ... + 50) = ${100×101}/2 - {50×51}/2$= 5050 – 1275 = 3775
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