Question
The sum of all the 3-digit numbers is
Answer: Option C
Answer: (c)First 3-digit number = 100Last 3-digit number = 999Number of terms = 900 S = $n/2(a+l)$= $900/2$[100 + 999] = 450 × 1099 = 494550
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Answer: (c)First 3-digit number = 100Last 3-digit number = 999Number of terms = 900 S = $n/2(a+l)$= $900/2$[100 + 999] = 450 × 1099 = 494550
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