Question
The sum of all natural numbers from 75 to 97 is :
Answer: Option D
Answer: (d)Series of all natural numbers from 75 to 97 is in A.P. whose first term, a = 75, last term, l = 97 If number of terms be n, then $a_n$ = a + (n–1)d97 = 75 + (n – 1) n = 97 – 74 = 23$S_n = n/2(a+l)$$S_23 = 23/2(75+97)$= $23/2$× 172=1978
Was this answer helpful ?
Answer: (d)Series of all natural numbers from 75 to 97 is in A.P. whose first term, a = 75, last term, l = 97 If number of terms be n, then $a_n$ = a + (n–1)d97 = 75 + (n – 1) n = 97 – 74 = 23$S_n = n/2(a+l)$$S_23 = 23/2(75+97)$= $23/2$× 172=1978
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution