Question
The sum invested in scheme B is thrice the sum invested in scheme A. The investment in scheme A is made for 4 years at 8% p.a. simple interest and in scheme B for 2 years at 13% p.a. simple interest. The total interest earned from both the schemes is Rs. 1320. How much amount was invested in scheme A?
Answer: Option A
Let the amount invested in scheme A be Rs. x and that in B be Rs. 3x.
Then,
$$\eqalign{
& = \frac{{x \times 4 \times 8}}{{100}} + \frac{{3x \times 2 \times 13}}{{100}} = 1320 \cr
& or,\,\frac{{32x}}{{100}} + \frac{{78x}}{{100}} = 1320 \cr
& or,\,\frac{{110x}}{{110}} = 1320 \cr
& \therefore x = \frac{{1320 \times 100}}{{110}} \cr
& = {\text{Rs}}{\text{. 1200}}. \cr} $$
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Let the amount invested in scheme A be Rs. x and that in B be Rs. 3x.
Then,
$$\eqalign{
& = \frac{{x \times 4 \times 8}}{{100}} + \frac{{3x \times 2 \times 13}}{{100}} = 1320 \cr
& or,\,\frac{{32x}}{{100}} + \frac{{78x}}{{100}} = 1320 \cr
& or,\,\frac{{110x}}{{110}} = 1320 \cr
& \therefore x = \frac{{1320 \times 100}}{{110}} \cr
& = {\text{Rs}}{\text{. 1200}}. \cr} $$
Was this answer helpful ?
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