Question
The simplified form of $(16^{3/2} + 16^{-3/2})$ is :
Answer: Option D
Answer: (d)$(16^{3/2} + 16^{-3/2})$= $(4^2)^{3/2} + 1/(16)^{3/2}$= $4^{2×3/2} + 1/4^{2×3/2} = 4^3 + 1/4^3$= $64 + 1/64 = {4096 + 1}/64 = 4097/64$
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Answer: (d)$(16^{3/2} + 16^{-3/2})$= $(4^2)^{3/2} + 1/(16)^{3/2}$= $4^{2×3/2} + 1/4^{2×3/2} = 4^3 + 1/4^3$= $64 + 1/64 = {4096 + 1}/64 = 4097/64$
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