Question
The ratio between a two-digit number and the sum of the digits of that number is 4 : 1.If the digit in the unit's place is 3 more than the digit in the ten's place, what is the number?
The ratio between a two-digit number and the sum of the digits of that number is 4 : 1.If the digit in the unit's place is 3 more than the digit in the ten's place, what is the number?
Answer: Option D
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Let the ten's digit be x. Then, unit's digit =(x+ 3).
Sum of the digits = x + (x + 3) = 2x + 3. Number = 10x + (x + 3)=11x + 3.
11x+3 / 2x + 3 = 4 /1 =↔11x + 3 = 4 (2x + 3)=↔3x = 9↔x = 3.
Hence, required number =11x + 3 = 36.
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