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Question
The product of two successive numbers is 4556. Which of the following is the larger of the two numbers?
Options:
A .  68
B .  67
C .  78
D .  63
E .  None of these
Answer: Option A


Let the two successive numbers be n, n + 1. It is given that n(n + 1) = 4556. => n2 + n - 4556 = 0=> n2 + 68n - 67n - 4556 = 0=> n(n + 68) - 67(n + 68) = 0=> n = 67 and (n + 1) = 68.



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