Question
The population of a town was 3600 three years back. It is 4800 right now. . What is the rate of growth of population, if it has been constant over the years and has been compounding annually?
Answer: Option D
:
D
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D
Option (d)
Conventional approach :
Final Value=Initial Value(1+r100)t
Thus, rate =(FVIV)1t−1
⇒FVIV=4836=1.33
Going from answer options
If 10 is the answer
1.13=112×11=12×11≈1.33
Therefore r is approximately 10%.
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