Question
The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is:
Answer: Option B
$$\eqalign{
& P{\left( {1 + \frac{{20}}{{100}}} \right)^n} > 2P\,\,\, \Rightarrow \,\,\,{\left( {\frac{6}{5}} \right)^n} > 2 \cr
& {\text{Now}},\left( {\frac{6}{5} \times \frac{6}{5} \times \frac{6}{5} \times \frac{6}{5}} \right) > 2 \cr
& So,\,n = 4\,{\text{years}} \cr} $$
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$$\eqalign{
& P{\left( {1 + \frac{{20}}{{100}}} \right)^n} > 2P\,\,\, \Rightarrow \,\,\,{\left( {\frac{6}{5}} \right)^n} > 2 \cr
& {\text{Now}},\left( {\frac{6}{5} \times \frac{6}{5} \times \frac{6}{5} \times \frac{6}{5}} \right) > 2 \cr
& So,\,n = 4\,{\text{years}} \cr} $$
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